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6v^2-10v-84=0
a = 6; b = -10; c = -84;
Δ = b2-4ac
Δ = -102-4·6·(-84)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-46}{2*6}=\frac{-36}{12} =-3 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+46}{2*6}=\frac{56}{12} =4+2/3 $
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